Convert xml to json without conversion String/Integer?

Question

I would like to convert XML to JSON.

Currently, I make this with the lib org.json :

JSONObject jso = XML.toJSONObject(xmlStr);

However, if the XML contains number fields, I would like to have only String fields in the JSONObject.

For example:

The XML file is :

<ID>3</ID>
<NAME>ApplicationName</NAME>

The org.json permits me to have:

{
    "ID" : 3,
    "Name" : "ApplicationName"
}

The final result has to be :

{
    "ID" : "3",
    "Name" : "ApplicationName"
}

That's a tough one. You might have more success deserializing the XML to a Map<String, String> to get everything to be String and then serializing that to JSON. Can't say for certain — jseashell
– jseashell, Commented Dec 19, 2016 at 15:15
Thanks. But it's possible to deserialize the XML file when it is more complexe than the exemple ? — J.Canonne
– J.Canonne, Commented Dec 19, 2016 at 15:27
I don't see why not. As long as it's a JSON Object and not a JSON Array, using the Map<String, String> should be fine — jseashell
– jseashell, Commented Dec 19, 2016 at 15:35

J.Canonne · Accepted Answer · 2016-12-19 16:33:43Z

7

I resolve mt problem by using the latest version of org.json.

There is a methode to do this :

JSONObject jso = XML.toJSONObject(xmlStr, true);

The boolean is using to keep the string fields.

answered Dec 19, 2016 at 16:33

J.Canonne

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1 Comment

which version is this one accept the boolean flag ? can you plese mentioned here ? we couldnt find in the latest version