Convert array of objects and their properties to array

Question

I tried several of the map functions but could not find a proper way to get what I want. Here is the case:

Object {Results:Array[3]}
   Results:Array[3]
       [0-2]
            0:Object
                   id=null     
                   name: "Rick"
                   upper:"0.67"
            1:Object
                   id="00379321"     
                   name:null
                   upper:"0.46"
            2:Object
                   id="00323113"      
                   name:null
                   upper:null

I want my final result to look like this. I wanted all null values to be removed and all the entries tied up like this in an object.

var finalResult = ["Rick","0.67","00379321","0.46","00323113"];

How can I achieve this result?

Andrey · Accepted Answer · 2016-07-07 14:52:04Z

3

_.chain(a)
.map(function(x) {return _.values(x)})
.flatten()
.filter(function(x) {return x != null;})
.value()

edited Jul 7, 2016 at 14:52

answered Jul 7, 2016 at 14:29

Andrey

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7 Comments

Heretic Monkey Over a year ago

Note that the "null" values in the example code are not actually null, but rather a string. Also, it's generally better to provide an explanation of the code, especially to people who are not familiar with the library.

Andrey Over a year ago

@MikeMcCaughan to people who are unfamiliar with library I always suggest to read docs first.

Heretic Monkey Over a year ago

Okay, but take a look at How to Answer, specifically Brevity is acceptable, but fuller explanations are better. It's obviously up to you how helpful you want to be, but this will likely end up on the Low Quality review queue due to being a code dump.

Patrick Over a year ago

@Andrey- this still shows null values at the final output when i do console.log(a); also i dont see any errors. am i doing anything wrong ?

Andrey Over a year ago

@Patrick I don't know what nulls you have exactly. Normal null value in JS is a value on its own, but in your example you have "null" as string. Adjust my code accordingly (4th line)

|

Alexey · Accepted Answer · 2016-07-07 14:58:27Z

3

Small modification for @andrey's code (requires lodash.js)

var a = [{id:null, name: "Rick", upper:"0.67"}, {id:"00379321", name:null, upper:"0.46"}, {id: "00323113",name:null, upper:null}]
_(a)
.map(function(x) {return _.values(x)})
.flatten()
.without(null)
.value()

edited Jul 7, 2016 at 14:58

answered Jul 7, 2016 at 14:34

Alexey

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2 Comments

Patrick Over a year ago

my apologies. The input in the console shows a bit different than wat i had earlier mentioned. Can you please have a look and let me know

Alexey Over a year ago

I updated my answer. I used different data in the array. Now it contains the same data and the result is the same

Nina Scholz · Accepted Answer · 2016-07-08 07:13:17Z

2

I suggest to use a fixed array for the keys, because the properties of an object have no order and the order is relevant.

var data = [{ id: null, name: "Rick", upper: "0.67" }, { id: "00379321", name: null, upper: "0.46" }, { id: "00323113", name: null, upper: null }],
    result = [];

data.forEach(function (a) {
    ['id', 'name', 'upper'].forEach(function (k) {
        if (a[k] !== null) {
            result.push(a[k]);
        }
    });
});

console.log(result);

edited Jul 8, 2016 at 7:13

answered Jul 7, 2016 at 14:32

Nina Scholz

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7 Comments

Patrick Over a year ago

it gives me an error stating data.forEach is not a function

Nina Scholz Over a year ago

which user agent do you use?

Patrick Over a year ago

didnt get you by user agent

Nina Scholz Over a year ago

what browser do you use?

Nina Scholz Over a year ago

its working fine with chrome 51.0.2704.106 m for windows.

|

Gruff Bunny · Accepted Answer · 2016-07-07 15:35:51Z

1

Another underscore solution, similar to the other underscore solutions, but uses reject and the isNull predicate:

var result = _.chain(data)
    .map(_.values)
    .flatten()
    .reject(_.isNull)
    .value();

answered Jul 7, 2016 at 15:35

Gruff Bunny

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