The source of question:LeetCode — 338. Counting Bits in c
The introduce: Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them as an array.
Example:For num = 5 you should return [0,1,1,2,1,2].
Follow up:
It is very easy to come up with a solution with run time O(n*sizeof(integer)). But can you do it in linear time O(n) /possibly in a single pass?
Space complexity should be O(n).
My code,appear Runtime Error when input 8(sometime 7), the result printf is true:
int* countBits(int num, int* returnSize) {
*returnSize=num+1;
int*arr=(int*)malloc(num+1);
arr[0]=0;
int i;
for(i=1;i<num+1;i++){
arr[i]=arr[i&(i-1)]+1;
printf("%d\n",arr[i]);
}
return arr;
}
int*arr=(int*)malloc(num+1);, useint* arr = malloc(sizeof *arr * (num+1u));