Php object not converting to array [duplicate]

Question

Actually i am not able to convert php object to array and specially when i have other access specifier. for example:

<?php

class Foo
{
    public $bar = 'barValue';
    protected $baz = 'bazValue';
    private $tab = 'tabValue';
}

$foo = new Foo();

$arrayFoo = (array) $foo;

echo "<pre>";
var_dump($arrayFoo);

and output is:

array(3) {
  ["bar"]=>
  string(8) "barValue"
  ["*baz"]=>
  string(8) "bazValue"
  ["Footab"]=>
  string(8) "tabValue"
}

so i am not able to get the key with its name, it automatic added * (for protected) and class name (for private),

as you have defines variables protected and private thats why its giving * , Foot in array indexes... — Dhara Parmar
– Dhara Parmar, Commented Jun 10, 2016 at 7:20

aslawin · Accepted Answer · 2016-06-10 07:24:52Z

2

You can use function mentioned in comments for get_object_vars PHP documentation:

function obj2array ( &$Instance ) {
    $clone = (array) $Instance;
    $rtn = array ();
    $rtn['___SOURCE_KEYS_'] = $clone;

    while ( list ($key, $value) = each ($clone) ) {
        $aux = explode ("\0", $key);
        $newkey = $aux[count($aux)-1];
        $rtn[$newkey] = &$rtn['___SOURCE_KEYS_'][$key];
    }

    return $rtn;
}

answered Jun 10, 2016 at 7:24

aslawin

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