I want check phone numbers. Right format is 38xxxxxxxxxx.
My check:
var phoneNumber=document.getElementById('phone').value;
var re=new RegExp("^[38]\d{10}$");
var res=phoneNumber.match(re);
I always get null. What's wrong?
-
learn to use regex101.com before coming and asking, it will save you and everyone else a bunch of time.user177800– user1778002016-05-02 18:45:52 +00:00Commented May 2, 2016 at 18:45
Add a comment
|
4 Answers
When using the RegExp constructor function with quotes, normal string escape rules apply. Thus, you need to escape the special character \d as \\d. Also you need to change [38] to simply 38, as [38] matches 3 or 8.
var str = '381234567890';
var re = new RegExp("^38\\d{10}$");
// or new RegExp(/^38\d{10}$/); without quotes
// or re = /^38\d{10}$/;
var res = str.match(re);
document.body.innerHTML = "Match result: " + res;Comments
var res=phoneNumber.match(/38[0-9]{8,10}/m);
phone number length allowed :10-12
Comments
Your regex is wrong, if you want to match 38xxxxxxxxxx you should remove [] brackets because this means 3 or 8 and afterwards it tries to match 10 digits, so just remove the []
var re=new RegExp("^38\d{10}$");
Comments
When using the constructor function, the normal string escape rules are necessary.
new RegExp("^38\\d{10}$");
