Iterating through JS Array + Array Properties

Question

I'm a bit of a novice I was hoping someone could point out what I am doing wrong.

The idea is for searchArray to loop through array values &properties. It takes the arguments (property, value). When I call the function I get a RefernencError saying that property(hostname) is undefined. Is there something wrong with browsingHistory[i].property?

function searchArray(property, value) {
    for (i = 0; i < browsingHistory.length; i++) {
        return value === browsingHistory[i].property;
    }
}

yes, browsingHistory is an array. it has objects in it with specific properties. — Henry Wartemberg
– Henry Wartemberg, Commented Apr 26, 2016 at 15:35

Apolo · Accepted Answer · 2016-04-26 16:03:57Z

3

browsingHistory[i].property means the value of the property called "property".

use browsingHistory[i][property] instead

Demo

function searchArray(property, value) {
    for (i = 0; i < my_array.length; i++) {
        return value === my_array[i][property];
    }
}


var my_array = [
  {
    x: "foo",
    y: "bar"
  },
  {
    x: "foooooo",
    y: "baaaaar"
  }
]


// should output "true" because my array contains an element with a 
// property named "x" and which value is "foo"
document.body.innerHTML = searchArray("x","foo");

edited Apr 26, 2016 at 16:03

answered Apr 26, 2016 at 15:32

Apolo

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4 Comments

Henry Wartemberg Over a year ago

I want it to point at the value of "property". basically I could check if the array has any objects with the host name : x

Apolo Over a year ago

check my demo, is that what you are looking for ?

Henry Wartemberg Over a year ago

Thank you! I was doing basically the same thing but I was calling searchArray( x, foo) didn't realise I needed to put it in speechmarks. I am curious as to why though

Apolo Over a year ago

because without quotes it is interpreted as an undeclared variable

Hazarapet Tunanyan · Accepted Answer · 2016-04-26 17:48:40Z

0

If you using a variable as a property of any object, you can use with "." syntax.You have to use it as array with that property (like array indexes).For example

var property = "name";
....
anyObject[property] // equals to anyObject['name'] or anyObject.name

answered Apr 26, 2016 at 17:48

Hazarapet Tunanyan

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