how to return a function inside a function javascript/nodejs?

Question

i am trying to return the url i get inside the getsignedurl. when i try this url1 is undefined

function getPublicUrl(filename) {
          var url1;
          var file = bucket.file(filename);

          file.getSignedUrl({
              action: 'read',
              expires: '03-17-2025'

          }, function (err, url) {
              if (err) {
                  console.error(err);
                  return;
              } else {
              url1  = url
                  console.log(url);

              }

          });
       return url1;
 }

then in another function i would call the getpublicurl

stream.on('finish', function() {
          req.file.cloudStorageObject = gcsname;
          req.file.cloudStoragePublicUrl = getPublicUrl(gcsname);

It looks like file.getSignedUrl is asynchronous, so return url1; is run before url1 is set in the callback function. — forgivenson
– forgivenson, Commented Mar 20, 2016 at 2:03

Ammar Hasan · Accepted Answer · 2016-03-20 02:02:34Z

1

file.getSignedUrl seems to be an asynchronous function, you can use ES6 Promise in getPublicUrl, some way like this

function getPublicUrl(filename) {
  return new Promise(function(resolve, reject) {
    var file = bucket.file(filename);
    file.getSignedUrl({
      action: 'read',
      expires: '03-17-2025'
    }, function(err, url) {
      if (err) {
        reject(err);
      } else {
        resolve(url);
      }

    });
  });
}

stream.on('finish', function() {
  getPublicUrl(gcsname).then(function(url) {
    console.log(url);
    req.file.cloudStorageObject = gcsname;
    req.file.cloudStoragePublicUrl = url;
  }).catch(function(err) {
    console.log(err);
  });
});

answered Mar 20, 2016 at 2:02

Ammar Hasan

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