Is there any way to send output of a program to another program in addition to STDOUT?

Question

I want to pipe the output of a program to another program in addition to STDOUT. The way I am doing it right now is to tee the output to a temporary file that I then delete but would be interested in knowing about better approaches where I don't have to create a temp file. Here is my code that shows what I am doing right now:

random=`echo $RANDOM`
filename='/tmp/'$random
foo | tee $filename
cat $filename | bar
rm $filename

In above foo and bar are my programs. What I want is to pipe the output of foo to bar but also have foo display its output to STDOUT. If I just do:

foo | bar

the output to STDOUT is lost.

have tee write to the process's console instead of a temp file? e.g. foo | tee /dev/tty | bar? — Marc B
– Marc B, Commented Feb 29, 2016 at 18:11

Felipe Lema · Accepted Answer · 2016-02-29 18:22:07Z

4

you can use process substitution:

foo | tee >(bar)

the >(…) syntax is for taking the bytes written to "this file" and giving them to the inner process

answered Feb 29, 2016 at 18:22

Felipe Lema

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Jay T. · Accepted Answer · 2016-02-29 18:15:36Z

0

foo can contain:

Message = $message ./bar.sh

bar can contain:

echo I received the \"$message"\

answered Feb 29, 2016 at 18:15

Jay T.

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