How do I sort an array of (Int, String) by Int value?

Question

var array = [(Int, String)]()

I need the pairs in the array sorted in ascending order by the value of the Int.

array = [(2, "is"), (0, "Hello"), (1, "this"), (3, "Ben")]

I need this to return:

array = [(0, "Hello"), (1, "this"), (2, "is"), (3, "Ben")]

I think some variation of the following should work, but I can't figure out how to set it up.

array.sortInPlace()

Eric Aya · Accepted Answer · 2015-12-10 18:37:56Z

6

let array = [(2, "is"), (0, "Hello"), (1, "this"), (3, "Ben")]
let sortedArray = array.sort { $0.0 < $1.0 }

print(sortedArray) // [(0, "Hello"), (1, "this"), (2, "is"), (3, "Ben")]

The .0 part represents the first object of the tuple.

See Matt's answer for the mutable version.

answered Dec 10, 2015 at 18:37

Eric Aya

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1 Comment

barrylachapelle Over a year ago

I'm not even joking when I say this answer (and question) changed my life. Tuples.

matt · Accepted Answer · 2015-12-10 18:38:09Z

2

Like this:

var array = [(2, "is"), (0, "Hello"), (1, "this"), (3, "Ben")]
array.sortInPlace{$0.0 < $1.0}

answered Dec 10, 2015 at 18:38

matt

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