Adding rows to table using jquery

Question

My button and table is as shown,

<button type="button" class="btn btn-md" id="addRowBtn">Test Button To Add Row</button>
<table id="tableForRows">
     <tr>
        <td>

        </td>
    </tr>
</table>

I want to keep adding text boxes on click of button..My jquery is as shown,

$(document).ready(function () {
    $("#addRowBtn").on("click", function () {
        var tableRow = $("#tableForRows").html();
        var itemToAdd = "<tr><td><input type="text"/></td></tr>";
       $("#tableForRows").append(itemToAdd);
    });
});

Help me know what the right way is..Thanks in advance..

This is a typo with your quotes. The syntax highlighting in your question shows that. — ssube
– ssube, Commented May 8, 2015 at 15:15

renakre · Accepted Answer · 2015-05-08 15:02:59Z

4

You have quotation problem, use single quotes for type='text':

"<tr><td><input type='text'/></td></tr>";

Also, based on what you shared, var tableRow = $("#tableForRows").html(); is redundant.

answered May 8, 2015 at 15:02

renakre

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1 Comment

Rizky Fakkel Over a year ago

To add to this, you can also use "<tr><td><input type=\"text\"/></td></tr>";. Using backslashes will escape the quote character.

Neoares · Accepted Answer · 2015-05-08 15:14:09Z

1

$(document).ready(function () {
    $("#addRowBtn").click(function () {
        var tr = document.createElement("tr");
        var td = document.createElement("td");
        var input = document.createElement("input");
        input.type = "text";
        $("#tableForRows").append(tr);
        $("#tableForRows tr:last-child").append(td);
        $("#tableForRows tr:last-child td:last-child").append(input);
    });
});

JSfiddle: https://jsfiddle.net/Neoares/Lo6p02oc/

answered May 8, 2015 at 15:14

Neoares

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1 Comment

ssube Over a year ago

You should add the input to the td, then the td to the tr, then the tr to the table. It will save you the last three selectors, which can be quite slow. Something like: jsfiddle.net/Lo6p02oc/2

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