get host name from domain REGEX javascript

Question

What i try to do is when i have:

www.gmail.com,

www.gmail.com/,

http://www.gmail.com,

https://www.gmail.com,

http://gmail.com,

https://gmail.com,

www.gmail.com/example

just get gmail.com, by far from searching into relative questions i have pattern to match these things which is:

var pat = /^(https?:\/\/)?(?:www\.)?([^\/]+)/;

but it also returns true when i put also a word eg. gmail (without .com). How can i improve this to match things that are of the form abcd.efgs.com ? I mean specify that the string should contain characters and at least one dot after the http,https,www. ?

Thanks in advance!

Community · Accepted Answer · 2020-06-20 09:12:55Z

5

If my understanding is right, you want to match only the domain names of a URL.

You can do this with this pattern

(?:\w+\.)+\w+

I have copied your JavaScript Fiddle and made changes to demonstrate this using html text and textarea boxes. The textbox demo, extracts the domain name from a user entered URL. The textarea box demo lists all the domains in the entered multiline text.

http://jsfiddle.net/q6z3xb6d/

[update]

Just read your question again. Looks like you want to exclude matches for domains beginning with www. You can use this pattern for that:

(?!(w+)\.)\w*(?:\w+\.)+\w+

JS fiddle demo - Updated version:

http://jsfiddle.net/q6z3xb6d/2/

edited Jun 20, 2020 at 9:12

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answered Oct 31, 2014 at 17:23

kums

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1 Comment

sstauross Over a year ago

your solution seems to work great! Thats what i expected.. Thanks a lot! i mark it as the correct answer to the original question.

vks · Accepted Answer · 2014-10-31 10:15:13Z

0

^(?:https?:\/\/)?(?:www\.)?((?:(?!www\.|\.).)+\.[a-zA-Z0-9.]+)

Try this.See demo.

http://regex101.com/r/yG7zB9/7

edited Oct 31, 2014 at 10:15

answered Oct 31, 2014 at 9:45

vks

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8 Comments

sstauross Over a year ago

its a good answer although when you put something like: www.gmail.example.com will return only gmail.example despite i would like to return the whole thing after www. could you edit it to take this into consideration?

sstauross Over a year ago

Perfect man! I would appreciate if you could explain to me where in this regex do you exclude the slash(/)? Edit your answer with the correct regex and i take it as accepted!:)

vks Over a year ago

@sstauross i am not actually excluding /.It just that [a-zA-Z0-9.] character class does not contain / so it cannot be matched.It will matchuntill it encounter a character out of the defined class

sstauross Over a year ago

Look at this fiddle: jsfiddle.net/6mrbbq9x when i try the regex does not actually return what i want, what am i doing wrong?

sstauross Over a year ago

Is there another way to get that? Because this: jsfiddle.net/6mrbbq9x/1 seems to partially work...

|

sstauross · Accepted Answer · 2014-10-31 15:28:04Z

Given an input field like:

<input type='text' id='domain'/>

i ended up with this solution in which i first validate it as a url and then get the string without 'http://', 'https://' , 'www.'

$(document).ready(function(){

function ValidUrl(str) {
  var pattern = new RegExp('^(https?:\\/\\/)?'+ // protocol
  '((([a-z\\d]([a-z\\d-]*[a-z\\d])*)\\.)+[a-z]{2,}|'+ // domain name
  '((\\d{1,3}\\.){3}\\d{1,3}))'+ // OR ip (v4) address
  '(\\:\\d+)?(\\/[-a-z\\d%_.~+]*)*'+ // port and path
  '(\\?[;&a-z\\d%_.~+=-]*)?'+ // query string
  '(\\#[-a-z\\d_]*)?$','i'); // fragment locator
  if(!pattern.test(str)) {
    return false;
  } else {
    return true;
  }
}

$('#domain').change(function(){
    var str = $.trim($(this).val());
    if(ValidUrl(str)){
       var pat = /^(https?:\/\/)?(?:www\.)?([^\/]+)/;
       var match = str.match(pat);
        console.log(match);
         //$(this).val(str);
    }
    else{
        $(this).val('Validation failed');
    }
});
});

See also this jsfiddle:http://jsfiddle.net/6mrbbq9x/5/

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