I have a python program that runs perfectly in Sublime text. The main function in the file has an argument (integer argument).
def main(number = input())
But when I tried to run it in command line such as,
$python testFile.py 56
It is giving me nothing. How is it possible to send an integer in the command line?
def main():
number = int(sys.argv[1]) # this line will fail if you pass an argument that's not an integer
print(number)
if __name__ == "__main__":
main()
import sys. And maybe do a check on len(sys.argv).What you want is sys.argv.
def main(number):
print int(number)
if __name__ == "__main__":
main(sys.argv[1])
Then you will be able to pass what you want in $python testFile.py 56
Your issue is that you're invoking your testFile.py and providing an argument before your script has started (and read from def main()).
There are a handful of approaches you can use, but the easiest may be just using sys.argv to get command line arguments, e.g.
def main():
number = int(sys.argv[1])
#this line calls main if you're calling the script directly:
if __name__ == '__main__':
main()
Note that it's poor form to give a mutable argument (e.g. 'input()') as a default in a method's signature.
sys.argv is a list - might want to check your notation :)As others have already suggested sys.argv can be used to get the command line arguments in your code.
But if for some odd reason you dont want to use that , you can also try passing the input using pipe in shell.
For example ,
$ echo '56' | python testFile.py
