How to sort an array in Javascript like C#?

Question

I would like to sort an array in JavaScript as asc. After I used sort method, the result is like below.

[ '123, '12', '1A1', '1A', '1a', 'A1', 'A2', 'AB', 'A', 'Ab', 'a1', 'a2', 'aB', 'ab' ]

When I'm using sort Array.Sort() by C#, the result is like below.

{ "12", "123", "1a", "1A", "1A1", "A", "a1", "A1", "a2", "A2", "ab", "aB", "Ab", "AB" }

Actually the C# sort way is what I want, so how to implement it in JavaScript? Has anyone completed this task before? A comparator function is really appreciate.

why this is down vote and the answers are up votes. Don't get it, write a new function is not the answer of the question. — mybirthname
– mybirthname, Commented Sep 13, 2014 at 10:05
@T.J.Crowder The order he specifies is actually what C# Array.Sort gives. — BLoB
– BLoB, Commented Sep 13, 2014 at 10:13
Have you notice that A is a single character? I guess so C# has special operation inside the sort method for it. Suppose C# sort is an expected result, now I want to use JavaScript to match it. — Damon
– Damon, Commented Sep 13, 2014 at 10:14
Here's the ideone.com for it... ideone.com/ZLKC8M It looks as though C# is ordering the string multiple times, going through the characters one by one, e.g. OrderBy([0]).ThenBy([1]).ThenBy([2]) and so on — BLoB
– BLoB, Commented Sep 13, 2014 at 10:16
@Damon I removed my question about writing own JavaScript function based on decompiled C# code. C# uses InternalCompareString Windows API function and there are too lot of conditions... It will be easier to write your own C# delegate function for sorting rather than investigate implementation of InternalCompareString Windows API. — Anton
– Anton, Commented Sep 13, 2014 at 11:07

Martin Probst · Accepted Answer · 2014-09-13 12:00:35Z

1

Array.prototype.sort uses string comparison by default. It seems you want to compare case insensitive - you could pass in a comparator function that uses toLowerCase (but beware of the difference with .toLocaleLowerCase!):

a.sort(function(a, b) {
  a = a.toLowerCase(); b = b.toLowerCase();
  return a > b ? 1 : a < b ? -1 : 0;
});

answered Sep 13, 2014 at 12:00

Martin Probst

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