How do I convert strings in an array to integers in an array in go?
["1", "2", "3"]
to
[1, 2, 3]
I've searched for some solutions online but couldn't find it. I've tried to loop through the array and did strconv.ParseFloat(v, 64) where v is the value but it didn't work.
You will have to loop through the slice indeed. If the slice only contains integers, no need of ParseFloat, Atoi is sufficient.
import "fmt"
import "strconv"
func main() {
var t = []string{"1", "2", "3"}
var t2 = []int{}
for _, i := range t {
j, err := strconv.Atoi(i)
if err != nil {
panic(err)
}
t2 = append(t2, j)
}
fmt.Println(t2)
}
On Playground.
For example,
package main
import (
"fmt"
"strconv"
)
func sliceAtoi(sa []string) ([]int, error) {
si := make([]int, 0, len(sa))
for _, a := range sa {
i, err := strconv.Atoi(a)
if err != nil {
return si, err
}
si = append(si, i)
}
return si, nil
}
func main() {
sa := []string{"1", "2", "3"}
si, err := sliceAtoi(sa)
if err != nil {
fmt.Println(err)
return
}
fmt.Printf("%q %v\n", sa, si)
}
Output:
["1" "2" "3"] [1 2 3]
Playground:
This is an ancient question but all the answers ignore the fact that the input length is known in advance, so it can be improved by pre-allocating the destination slice:
package main
import "fmt"
import "strconv"
func main() {
var t = []string{"1", "2", "3"}
var t2 = make([]int, len(t))
for idx, i := range t {
j, err := strconv.Atoi(i)
if err != nil {
panic(err)
}
t2[idx] = j
}
fmt.Println(t2)
}
Playground: https://play.golang.org/p/LBKnVdi_1Xz
A slice is a descriptor of an array segment
It consists of
- a pointer to the array,
- the length of the segment, and
- its capacity (the maximum length of the segment)
Below, string Array/Slice is converted to int Array/Slice:
package main
import (
"fmt"
"log"
"strconv"
"strings"
)
func Slice_Atoi(strArr []string) ([]int, error) {
// NOTE: Read Arr as Slice as you like
var str string // O
var i int // O
var err error // O
iArr := make([]int, 0, len(strArr))
for _, str = range strArr {
i, err = strconv.Atoi(str)
if err != nil {
return nil, err // O
}
iArr = append(iArr, i)
}
return iArr, nil
}
func main() {
strArr := []string{
"0 0 24 3 15",
"0 0 2 5 1 5 11 13",
}
for i := 0; i < len(strArr); i++ {
iArr, err := Slice_Atoi(strings.Split(strArr[i], " "))
if err != nil {
log.Print("Slice_Atoi failed: ", err)
return
}
fmt.Println(iArr)
}
}
Output:
[0 0 24 3 15]
[0 0 2 5 1 5 11 13]
I used in a project, so did a small optimizations from other replies, marked as // O for above, also fixed a bit in readability for others
Best of luck
Here is another example how to do this:
var t = []string{"1", "2", "3"}
str := strings.Join(t, "")
if _, err := strconv.Atoi(str); err != nil {
// do stuff, in case str can not be converted to an int
}
var slice []int // empty slice
for _, digit := range str {
slice = append(slice, int(digit)-int('0')) // build up slice
}
I like this because you have to check only once if each digit inside of t can be converted to an int. Is it more efficient? I don`t know.
Why do you need the int('0')? Because int() will convert the character to the corresponding ASCII code (ascii table here). For 0 that would be 48. So you will have to substract 48 from whatever your digit corresponds to in "ascii decimal".
