Java URL creating from few strings

Question

I want to create URL using : existing url and 2 strings

I found

Create URL from a String

and

File.separator or File.pathSeparator

but I want to create it without typing '/'

String part1 = "txt1";

String part2 = "txt2";

URL urlBase = new URL(some adress);

now I can write

URL urlNew = urlBase.toURI().resolve(part1).toURL();

but how to add part2 goal is to get adress/txt1/txt2

Your question is difficult to read. Is what you want: URL urlNew = urlBase.toURI().resolve(part1 + "/" + part2).toURL();? — Cruncher
– Cruncher, Commented Jul 14, 2014 at 18:46
Hi, thanks for reply, solution is correct but I want to achieve same result without usage of '/'. Do you know how to do that ? — Arkadiusz Eric
– Arkadiusz Eric, Commented Jul 15, 2014 at 19:29
URL urlNew = urlBase.toURI().resolve(part1 + (char)47 + part2).toURL(); — Cruncher
– Cruncher, Commented Jul 15, 2014 at 19:34
That was a joke comment btw. http://docs.oracle.com/javase/7/docs/api/java/net/URI.html#relativize(java.net.URI) might be useful. But I don't know this API very well. — Cruncher
– Cruncher, Commented Jul 15, 2014 at 19:37
does URL urlNew = urlBase.toURI().resolve(part1).resolve(part2).toURL(); work? — Cruncher
– Cruncher, Commented Jul 15, 2014 at 19:38

Soley · Accepted Answer · 2014-07-14 18:47:51Z

0

Will this help?

public static void main(String[] args) throws MalformedURLException {
        URL domain = new URL("http://google.com");
        URL url = new URL(domain, "test");
        System.out.println(url.toString());
    }

Or

public static void main(String[] args) throws MalformedURLException {
        URL domain = new URL("http://google.com/sample/text/a");
        URL url = new URL(domain, "test");
        System.out.println(url.toString());
    }

Notice that it will add the string to your domain.

answered Jul 14, 2014 at 18:47

Soley

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1 Comment

Arkadiusz Eric Over a year ago

Thanks for reply, result : google.com/sample/text/test, but I want to get google.com/sample/text/a/test. 'Cruncher' solution is correct but it involves usage of '/' that like I wrote I'm trying to avoid (assumption: we can do this without typing '/')

Soley · Accepted Answer · 2014-07-16 17:42:33Z

What about this?

public static void main(String[] args) throws Exception {
    URL urlBase = new URL("http://google.com/2");
    String part1 = "test1/3";
    String part2 = "test2";
    System.out.println(
            urlBase.toString()
            + new URL(urlBase, part1).getPath()
            + new URL(urlBase, part2).getPath()
        );
}

No character is required :)

If you have an empty string, it won't work, so this is the solution for it:

public static void main(String[] args) throws Exception {
        URL urlBase = new URL("http://google.com/2");
        String part1 = "test1/3";
        String part2 = "test2";
        System.out.println(
                urlBase.toString()
                + (part1.isEmpty() ? "" : new URL(urlBase, part1).getPath())
                + (part2.isEmpty() ? "" : new URL(urlBase, part2).getPath())
            );
    }

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