var exampleURL = '/example/url/345234/test/';
var numbersOnly = [?]
The /url/ and /test portions of the path will always be the same.
Note that I need the numbers between /url/ and /test. In the example URL above, the placeholder word example might be numbers too from time to time but in that case it shouldn't be matched. Only the numbers between /url/ and /test.
Thanks!
var exampleURL = '/example/url/345234/test/';
// this will remove all non-numbers
var numbers = exampleURL.replace(/[\D]/g, '');
// or you can split the string and take only that 3rd bit
var numbers = exampleURL.split(/\//)[3];
// or match with a regex
var numbers = exampleURL.match(/\/(\d+)\/test\//)[1];
Something along these lines:
var result;
result = value.match(/\/url\/([0-9]+)\/test/);
// use result[1] to get the numbers (the first capture group)
That relies on the /url/ and /test bits, since you said they were reliable. More generally, this will match the first run of digits in the string:
var result;
result = value.match(/[0-9]+/);
// use result[0] (not result[1]), which is the total match
The MDC page on regular expressions is pretty useful.
Note: Instead of [0-9] above, you can use \d which stands for "digit". I don't because my regex-fu is weak and I can never remember it (and when I do, I can never remember whether it's all digits or all non-digits [which is \D -- you see my confusion]. I find [0-9] really clear when I read it later. Others may find \d clearer, but for me, I like the explicit-ness of listing the range.
regex that would work is
matches = exampleURL.match('/\/.+\/url/([0-9]+)\/test\//');
I think that's right.
