How to get width of an element from an ng-click without Jquery in AngularJS?

Question

I would like to get dynamically the width of the div.progress-bar from the ng-click. My function move($event) on the element div.progress-bar returns the event with the element div.progress-bar. But when I click on div.time which is inside div.progress-bar, it returns the event with the element div.time.

I just want the width of the progress-bar even I click on his children.

HTML :

    <div class="progress-bar" ng-click="move($event)">
        <div class="time" ng-style="{'width': (current_track.time_current / current_track.time_total * 100) + '%'}"></div>
    </div>

CONTROLLER :

$scope.move = function(e) {
    console.log(e);
    console.log(e.srcElement.offsetWidth);
    var widthOfProgressBar = e.srcElement.offsetWidth;
    /* ... */
};

VisioN · Accepted Answer · 2014-06-27 09:19:04Z

2

You have to check if the clicked element is .progress-bar, and if it is not, fetch the parent element:

var bar = e.srcElement.className === 'time'
    ? e.srcElement.parentNode
    : e.srcElement;

var widthOfProgressBar = bar.offsetWidth;
/* ... */

Or alternative more Angular/jqLite way:

var element = angular.element(e.srcElement),
    bar = (element.hasClass('time') ? element.parent() : element)[0];

var widthOfProgressBar = bar.offsetWidth;
/* ... */

edited Jun 27, 2014 at 9:19

answered Jun 27, 2014 at 9:07

VisioN

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1 Comment

Steffi Over a year ago

Great answer @VisioN ! I take the first solution ;)

Eyad Farra · Accepted Answer · 2014-11-01 07:35:48Z

0

$scope.move =  function(e){
    var width = angular.element(e.srcElement)[0].offsetWidth;

    console.log(e.offsetX ,"/", width);
}

answered Nov 1, 2014 at 7:35

Eyad Farra

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