How to call a shell script from another shell script based on the first script's result?

Question

Shell script 1.sh is like

#/bin/bash

if some java command;
then 
exit 1;
else    
exit 0;
fi

Shell script 2.sh will determine its execution based on the result (1 or 0) from 1.sh

#/bin/bash
readyToDoSomethingIfOne=$(1.sh)

if($readyToDoSomethingIfOne=="1");
then
echo "ready to go";
else    
echo "Not ready yet" ;
fi

It looks like exit command from 1.sh does not pass the value to 2.sh. Is there any good way to do so?

By the way, 1.sh and 2.sh have to be separated for business reasons.

Thanks

The exit status is $?, not captured in $() (which gets content sent to stdout). In general, though, if you wanted to know if something succeeded or not, you don't need to check $? explicitly -- if some_command will take the true branch if $? is 0 after running some_command, the else branch otherwise. — Charles Duffy
– Charles Duffy, Commented Mar 21, 2014 at 19:03
By the way, bash scripts shouldn't be named with .sh extensions -- first, commands don't conventionally have extensions at all in UNIX (you don't run ls.elf); second, bash is not POSIX sh, and someone running sh foo.sh rather than bash foo.sh would be in for an unwelcome surprise if you used any features not available in the barebones standard form of the language. — Charles Duffy
– Charles Duffy, Commented Mar 21, 2014 at 19:05
By the way, exit 0 should be used on success, and exit 1 on failure. — Charles Duffy
– Charles Duffy, Commented Mar 21, 2014 at 19:10

Charles Duffy · Accepted Answer · 2014-03-21 19:03:13Z

2

#/bin/bash

if 1.sh; then
  echo "ready to go";
else    
  echo "Not ready yet" ;
fi

answered Mar 21, 2014 at 19:03

Charles Duffy

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2 Comments

devnull Over a year ago

While your answer is correct, you need to say if ! 1.sh in order to comply with OPs return convention. (Take a look at OPs script 1; it returns with an exit code of 1 in case the command is successful :) )

Charles Duffy Over a year ago

@devnull, I'm going to leave this as-is, and upvote your comment. Better for the OP to fix their code.

5gon12eder · Accepted Answer · 2014-03-21 19:07:53Z

0

The construct

VAR=$(COMMAND)

assigns the output of COMMAND to the variable VAR. You can get the exit status of the last command from the automatic variable $?. That is

COMMAND
case $? in
  0)
      # do this
      ;;
  1)
      # do that
      ;;
  *)
      # do something else
      ;;
esac

If you only want to distinguish between success ($? == 0) and failure ($? != 0) then you can use the simpler if construct as in your script1.sh.

If using $?, watch out that it changes after every command, so if you need the value for later use, save it in a variable.

COMMAND
status=$?
# now use $status

answered Mar 21, 2014 at 19:07

5gon12eder

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Comments

kojiro · Accepted Answer · 2014-03-21 19:09:15Z

0

#/bin/bash
if readyToDoSomethingIfOne=$(1.sh); then # Just use the exit status of the initial script directly.
    …
else
    echo 'nope!'
fi

If you don't actually need the variable at all, just run the script like this:

if ./1.sh; then
  echo "Not ready yet"
  return / exit / continue # Not enough context to know which exit approach is best.
fi

edited Mar 21, 2014 at 19:09

answered Mar 21, 2014 at 19:01

kojiro

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