Having issue running JAVA program inside BASH script

Question

I have a bash script that look like below. All I am doing here is trying to run a java program passing in classpath and other inputs.

[guest@server1]# cat runJava
#!/bin/bash
JARS=/home/guest/lib/*
CONFIG=/home/guest/AnalyticServer.properties

echo JARS=$JARS
echo CONFIG=$CONFIG
echo "java -cp \"$JARS\" com.test.ASDataSourceClient DELETE -c \"$CONFIG\" -n test_ds"
java -cp "$JARS" com.test.ASDataSourceClient DELETE -c "$CONFIG" -n test_ds

The java program runs perfectly fine when run directly on command line/terminal. I even tested running all the commands from above script on terminal directly(one by one) and verified that java program runs fine. However, when I launch these commands via script, I am having issue. It doesn't even seem to execute echo "java -cp .." command properly.

Could anyone advice what I may be missing.

[guest@server1]# bash runJava
JARS=/home/guest/lib/*
CONFIG=/home/guest/AnalyticServer.properties
" -n test_dsaSourceClient DELETE -c "/home/guest/AnalyticServer.properties
Exception in thread "main" java.lang.NoClassDefFoundError: com/test/ASDataSourceClient
Caused by: java.lang.ClassNotFoundException: com.test.ASDataSourceClient
    at java.net.URLClassLoader$1.run(URLClassLoader.java:202)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.net.URLClassLoader.findClass(URLClassLoader.java:190)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
    at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:247)
Could not find the main class: com.test.ASDataSourceClient.  Program will exit.

Your echo is fine and should be showing. The error message is from java. How are you running the scripts? — Tracy Snell
– Tracy Snell, Commented Feb 3, 2014 at 18:26

glenn jackman · Accepted Answer · 2014-02-03 19:04:22Z

3

Due to the way globbing works, JARS=/home/guest/lib/* won't do what you want.

Instead, you can use either

JARS=(/home/guest/lib/*)  # Put all the jars in an array 
IFS=:                     # Set the field separator to :
java -cp "${JARS[*]}" ... # Join all the array elements on the field separator

or less obscurely

JARS=""
for jar in /home/guest/lib/* # Loop through all the jar files
do
    JARS="$JARS:$jar"        # Append the jar file to the variable
done 
java -cp "$JARS" ...

This will make the JARS variable contain a colon separated list of jar files.

edited Feb 3, 2014 at 19:04

glenn jackman

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answered Feb 3, 2014 at 18:19

that other guy

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1 Comment

glenn jackman Over a year ago

You can also do string contatenation with: JARS+=":$jar" -- not sure what version of bash that requires. Also, trim the leading colon with "${JARS#:}"

Grzegorz Oledzki · Accepted Answer · 2014-02-03 18:06:08Z

1

It's not enough to point to the directory containing JARs. You need to name them explicitly, e.g.

JARS="/home/guest/lib/spring-beans-3.0.5.jar:anotherlibrary.jar"

answered Feb 3, 2014 at 18:06

Grzegorz Oledzki

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1 Comment

Deeps Over a year ago

Thanks, I would try that method but don't understand why * wouldn't get expanded to look for all the jar files in that directory.

glenn jackman · Accepted Answer · 2014-02-03 19:10:19Z

0

I notice this odd line in your script output:

" -n test_dsaSourceClient DELETE -c "/home/guest/AnalyticServer.properties

That indicates $CONFIG ends with a \r character. Are you editing this script in a Windows text editor? Remove carriage returns in your script with dos2unix

answered Feb 3, 2014 at 19:10

glenn jackman

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Comments

vzamanillo · Accepted Answer · 2014-02-03 18:18:19Z

-1

Try this

#!/bin/bash

JARS=/home/guest/lib
CONFIG=/home/guest/AnalyticServer.properties

echo JARS=$JARS
echo CONFIG=$CONFIG

for file in `ls $JARS/*.jar`;
do
    classpath=$classpath:$file
done

cmd="java -classpath $classpath com.test.ASDataSourceClient DELETE -c $CONFIG -n test_ds"
echo $cmd
exec $cmd

answered Feb 3, 2014 at 18:18

vzamanillo

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1 Comment

chepner Over a year ago

There are two problems with this answer: iterating over the output of ls, and relying on the word-split expansion of a parameter to be equivalent to the original command line. Both will break when they involve file names that contain whitespace.

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