JQuery code to disable input field with a check box not working

Question

I'm trying to disable the price input field when the checkbox is ticked and remove any text. I don't know what I'm doing wrong here..

<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script type="text/javascript">
    $('#confP').change(function(){
        if ($('#confP').is(':checked') == true){
            $('#price').val('').prop('disabled', true);
            console.log('checked');
        } else {
            $('#price').prop('disabled', false);
            console.log('unchecked');
        }
    });
</script>

<input type="checkbox" id="confP" name="confP" value="productType"?>Configurable Product?

Price <input type="text" id="price" name="price"/>

Your code working correctly. Try this one jsfiddle.net/2s7Kr — Ishan Jain
– Ishan Jain, Commented Jan 11, 2014 at 21:03

Mutant · Accepted Answer · 2014-01-11 20:54:01Z

1

Specify your script content in $(document).ready(function(){...});

$(document).ready(function(){
    $('#confP').change(function(){
        if ($('#confP').is(':checked') == true){
            $('#price').val('').prop('disabled', true);
            console.log('checked');
        } else {
            $('#price').prop('disabled', false);
            console.log('unchecked');
        }
    });
  });

answered Jan 11, 2014 at 20:54

Mutant

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2 Comments

ethio Over a year ago

The example on JQuery.com for change() doesn't have this, why must I use it to make it work?

Mutant Over a year ago

because it make sure that the page is loaded and document is ready. So $('#confP') will be able to find the element and bind the event. You can try to placing debugger; before that line and see in case of without document.ready it wont find the element #confP so it wont be able to bind the event.

Muhammad Rashid · Accepted Answer · 2014-01-11 20:54:40Z

1

Try this,you missed $( document ).ready(function() { Fiddle

<script src="http://code.jquery.com/jquery-1.9.1.js"></script>

<script type="text/javascript">
$( document ).ready(function() {
    $('#confP').change(function(){
        if ($('#confP').is(':checked') == true){
            $('#price').val('').prop('disabled', true);
            console.log('checked');
        } else {
            $('#price').prop('disabled', false);
            console.log('unchecked');
        }
    });
 });
</script>

<input type="checkbox" id="confP" name="confP" value="productType"?>Configurable Product?

Price <input type="text" id="price" name="price"/>

answered Jan 11, 2014 at 20:54

Muhammad Rashid

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1 Comment

ethio Over a year ago

The example on JQuery.com for change() doesn't have this, why must I use it to make it work?

TonyMtz · Accepted Answer · 2014-01-11 20:49:04Z

-1

Use this to disable:

$('#price').attr('disabled', true);

And this to enable later:

$('#price').removeAttr('disabled');

Cheers.

edited Jan 11, 2014 at 20:49

answered Jan 11, 2014 at 20:36

TonyMtz

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