Syntax Error in bash while loop

Question

What is the error in that?

j=0
filenames=("")
filedates=("")

while read line
do
filenames[$j]="$line"
filedates[$j]=$(stat -c %y ${filenames[$j]} | cut -d ' ' -f1)
(( j++ ))
done < <(ls -t *.gz)

Out:

script.sh: line 9: syntax error near unexpected token `<'
script.sh: line 9: `done < <(ls -t *.gz)'

Really i don't know the error in that while loop, i tested it on several machine but same problem

that other guy · Accepted Answer · 2014-01-10 01:28:29Z

2

The problem is that you're using bash specific <(process substition), but running your script with /bin/sh.

Use bash script.sh instead of sh script.sh, and make sure the shebang uses bash and not sh.

answered Jan 10, 2014 at 1:28

that other guy

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Comments

kurumi · Accepted Answer · 2014-01-10 00:26:58Z

1

use a for loop

for file in *t.gz
do
   ...
done

answered Jan 10, 2014 at 0:26

kurumi

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2 Comments

user3178889 Over a year ago

am still dummy in bash, can u please right the whole loop for me?

Dennis Meng Over a year ago

@user3178889 That would be a completely different thing altogether, and cause you to miss out on a valuable learning opportunity. We were all dummies once.

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