How To Return an Array from PHP to Javascript

Question

This is the PHP code

I Don't Know why it was running and suddenly it don't need to run anymore, In addtion to that the result is not as i need i need to say as example:

alert(rs[0]); //and the alert result is 1
alert(rs[1]); //and the alert result is 2

Any Suggestions ?

Your code looks fine. Check if your AJAX request fails. See if you get an error. Check the raw value of request.responseText. You know, basic debug stuff. — Halcyon
– Halcyon, Commented Jan 7, 2014 at 13:58
looks completely fine, but rs = new Array(); is unnessecary, simply just var rs = JSON.parse(ajaxRequest.responseText); — davidkonrad
– davidkonrad, Commented Jan 7, 2014 at 14:04

user2211216 · Accepted Answer · 2014-01-07 14:08:54Z

1

use:

rs = JSON.parse(xmlhttp.responseText);

instead of

rs = JSON.parse(ajaxRequest.responseText);

at line 19, the ajax object is xmlhttp in your case, ajaxRequest is undefined

answered Jan 7, 2014 at 14:08

user2211216

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2 Comments

Abdel-rahman El-Carpenter Over a year ago

fine nw if i need to return indexed array from php i.e. (key, value) how can i make JS understand it for example i want to say (Var ob = JSON.parse(xmlhttp.responseText); ) then i wanna to alert ob.name ??

davidkonrad Over a year ago

+1 for answer @Abdel-rahmanEl-Carpenter - ob[0].name will return the first name in your JSON "array".

Dipak · Accepted Answer · 2014-01-07 14:02:57Z

0

while (obj.length > 0) {

        var obj_new = obj.pop();

       document.getElementById("category_level_2").innerHTML += '<option  value="'+obj_new['ID']+'">'+obj_new['Name_category']+'</option>';   

        }

By using obj.pop() you can fetch an array.

answered Jan 7, 2014 at 14:02

Dipak

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