ASP.NET MVC4 @MvcHtmlString.Create() issues with @Html.RenderPartial()

Question

I am trying to dynamically render pages from database. The view looks like this

@model MyModel

@{
    ViewBag.Title = Model.Title;
    Layout = Layout = "~/Views/Shared/_PageInnerLayout.cshtml";
}

@MvcHtmlString.Create(Model.Content)

MyModel has just 3 properties; Id, Title and Content

If the Content has just HTML, the view renders just fine. But in some cases, I need to render partials too. So Content may contain code like

@{
    Html.RenderPartial("_FooterPartial");
}

This does not work. Its being rendered literally, like shown in the image below

Example of rendered page

How do I fix this so that the page is rendered properly?

you can add flag for example IsPartialContent to model, and if it is true then render partial manualy, also you can see on razorgenerator — Grundy
– Grundy, Commented Dec 7, 2013 at 7:00
@Grundy I didn't quite understand your answer. Can you please elaborate? — Vivek
– Vivek, Commented Dec 7, 2013 at 7:08
I misunderstood, I thought that the content can only be html or a line renderpartial with no other html code — Grundy
– Grundy, Commented Dec 7, 2013 at 7:12
@MvcHtmlString.Create put string in output as is, so if you want put not only html you must process your Model.Content for example in razor engine, and output result string — Grundy
– Grundy, Commented Dec 7, 2013 at 14:05

Community · Accepted Answer · 2017-05-23 12:21:39Z

1

The problem is in the difference between Html.RenderPartial and Html.Partial helper methods. RenderPartial directly write the result to HttpContext.Response while Partial return it as a MvcHtmlString. You need to replace the RenderPartial with Partial and maybe the RenderAction with Action.

Edited:

You need to render the content if contains the razor view scripts. If so it means you are actually storing the views or partial views inside the database. You can create a new VirtualPathProvider to help loading the views from the database. For more information see ASP.NET MVC load the Razor views from database and ASP.NET MVC and virtual view

edited May 23, 2017 at 12:21

CommunityBot

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answered Dec 7, 2013 at 13:22

Kambiz Shahim

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2 Comments

Kambiz Shahim Over a year ago

@Vivek You need to render the content of Model.Content as a view if it contains the razor view scripts, inside the controller's action before pass it to view.

Vivek Over a year ago

Well, it didn't work. I implemented a VirtualPathProvider and it still wouldn't render Razor Code

Vivek · Accepted Answer · 2013-12-09 12:41:04Z

0

I tried doing this with VirtualPathProvider, but it didn't work.

Finally what I did was to write the Content from database into a temporary view and then render the view. It worked

public ActionResult DynamicPage(int id) {
  var dynamicPage = new PagesContext().Pages.FirstOrDefault(s => s.Id == id);

  string webroot = Server.MapPath("~").TrimEnd('\\');
  string fileName = webroot + "\\Views\\\\Solutions\\Temp.cshtml";

  System.IO.File.WriteAllText(fileName, dynamicPage.Content);
  return View("Temp");
}

Here, the Content property of the dynamicPage containts HTML(including Razor code)

answered Dec 9, 2013 at 12:41

Vivek

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2 Comments

Kambiz Shahim Over a year ago

I beg to disagree, this solution has performance issue and it is not thread safe also. The multiple requests executing in the multiple threads try to write to a single file leads to the synchronization issues.

Vivek Over a year ago

@KambizShahim Yes. That is an issue. Any suggestions please?

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