How do I get the class attribute value using jquery and javascript

Question

I'm trying to get the class of the selected option and use that in a compare statement to find which class it is.

I get an undefined value. The option tag has a class set to it.

Why am I not getting a value back?

Html:

<select name="datagrid_filter" onchange="startFilter();">
    <option>All</option>
    <option disabled="true">Assignment:</option>
    <option disabled="true">Client:</option>
    <option disabled="true">Type:</option>
    <option class="type" value="Activity"> &nbsp Activity</option>
    <option class="type" value="Alert"> &nbsp Alert</option>
    <option class="type" value="Lead"> &nbsp Lead</option>
    <option class="type" value="Notification"> &nbsp Notification</option>
</select>

Javascript:

var cs1 = $("option:selected", this).attr("class");
if(cs1 == 'Type'){
    //do something
}

change 'Type' to 'type' in js

Nishad K Ahamed
– Nishad K Ahamed

2013-09-21 14:14:44 +00:00
Commented Sep 21, 2013 at 14:14 — Nishad K Ahamed
– Nishad K Ahamed, Commented Sep 21, 2013 at 14:14
i made the change, but the problem is that cs1 is undefined

user2671355
– user2671355

2013-09-21 14:20:11 +00:00
Commented Sep 21, 2013 at 14:20 — user2671355
– user2671355, Commented Sep 21, 2013 at 14:20

Tho · Accepted Answer · 2020-07-07 00:36:41Z

18

You should change:

onchange="startFilter();" to onchange="startFilter(this);"

and in startFilter function:

function startFilter(ele){
    var className = $("option:selected", ele).attr("class");
    if(className == 'type'){
        //do something
    }
}

Take note that, the this inside startFilter function refers to the window object, not the element you bind it to.

edited Jul 7, 2020 at 0:36

answered Sep 21, 2013 at 14:40

Tho

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1 Comment

user2671355 Over a year ago

Worked great, like in the above statement, I was referring to wrong object with my this. Needed to make sure right object was referenced. thanks

frogatto · Accepted Answer · 2015-06-24 12:28:42Z

1

Why don't you use hasClass jQuery API? It's very good in this case:

if($("option:selected", this).hasClass('type')){
    //do something
}

And make sure this referes to a proper object (as @undefined mentioned)
Or use:

if($("option:selected", "select[name=datagrid_filter]").hasClass('type')){
        //do something
    }

Or:

if($("select[name=datagrid_filter] option:selected").hasClass('type')){
            //do something
 }

edited Jun 24, 2015 at 12:28

answered Sep 21, 2013 at 14:35

frogatto

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Comments

Tomas Santos · Accepted Answer · 2013-09-21 14:46:02Z

Try not to have inline JavaScript

Fiddle Demo

JavaScript

   $(function()
    {
        var handleChange    =   function()
                                {
                                    var $this     = $(this);
                                    var $selected = $this.children(":selected");
                                    var isType    = $selected.hasClass('type');
                                    if(isType)
                                    {
                                        alert('Do Something');                        
                                    }
                                };
        var $datagridFilter =  $('[name=datagrid_filter]')

        $datagridFilter.change(handleChange);

    });

nirali · Accepted Answer · 2018-12-19 05:36:08Z

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<select onchange="getval(this);" class="sele">
   <option>All</option>
    <option disabled="true">Assignment:</option>
    <option disabled="true">Client:</option>
    <option disabled="true">Type:</option>
    <option class="type" value="Activity"> &nbsp Activity</option>
    <option class="type" value="Alert"> &nbsp Alert</option>
    <option class="type" value="Lead"> &nbsp Lead</option>
    <option class="type" value="Notification"> &nbsp Notification</option>
</select>
<script>
 function getval(sel)
{

    if($('.sele :selected').attr('class'))
    {
      console.log($('.sele :selected').attr("class","typ123"));
          // Your code write here
    }

}
</script>

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