gdb python: How to do arithmetic operation on a gdb.value?

Question

why i am getting wrong answer while doing arithmetic operation:

(gdb) python address = gdb.parse_and_eval('&(((struct my_struct *)next->priv).wait_list)')
(gdb) python print address
0x410027a00728
(gdb) python offset = gdb.parse_and_eval('&((struct wait_list_t *)0)->list')
(gdb) python print offset
0x0
(gdb) python diff = address - offset
gdb) python print diff
0x410027a0072

while output should be 0x410027a00728. i checked the type of address and offset by

(gdb) python print address.type
struct list_head *
(gdb) python print offset.type
struct list_head *

I tried this also

(gdb) python y = hex(long(address))
(gdb) python print y
0x410027A14FF0L
(gdb) python z = hex(long(offset))
(gdb) python print z
0x0L
(gdb) python diff = y - z
Traceback (most recent call last):
File "<string>", line 1, in ?
TypeError: unsupported operand type(s) for -: 'str' and 'str'
Error while executing Python code.

Is there any alternative to do this ?

Does python diff = long(address) - long(offset) work?

user4815162342
– user4815162342

2013-06-26 13:40:23 +00:00
Commented Jun 26, 2013 at 13:40 — user4815162342
– user4815162342, Commented Jun 26, 2013 at 13:40
Thanks.:-) It worked exactly what i wanted.

Baijnath Jaiswal
– Baijnath Jaiswal

2013-06-26 14:22:50 +00:00
Commented Jun 26, 2013 at 14:22 — Baijnath Jaiswal
– Baijnath Jaiswal, Commented Jun 26, 2013 at 14:22

Tom Tromey · Accepted Answer · 2013-06-26 13:40:24Z

1

You are subtracting two values of pointer type. This means that the result, as in C, is divided by the size of the object.

Instead, ensure that "offset" has an integral type, not a pointer type.

In the last example you are trying to subtract strings. You can't do that. Move the calls to "hex" from the computations to the prints and it will work.

answered Jun 26, 2013 at 13:40

Tom Tromey

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2 Comments

Baijnath Jaiswal Over a year ago

tromey,in the script print-struct-follow-pointers.py written here stackoverflow.com/questions/16787289/… ,similar to is_pointer(v)condition in script, i am checking one more condition by if is_typedef(v): type_ = v.type.strip_typedefs() print 'type = %s'%(type_) in the case of some structs, it prints correct type, but for some structs it prints type = struct {...} . i am not able to find the exact reason..

Baijnath Jaiswal Over a year ago

solved.:-) it was because of anonymous structure.. !! is there no support for python keyword with and as inside gdb? why is it not working ? code is here stackoverflow.com/questions/17448736/…

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