Change image using multiple select and javascript

Question

I need to change the image on my website using 2 select for colour and size.

e.g. If I choose the option "Red" under the colour select, and then I choose the option "Small" under the size select, the image should be "small_red.png". Similarly, if I choose red and large, then the image should be "red_large.png"

Thus far, I only know how to do it for 1 select, but not multiple select.

Here's my html:

<img id="imageToSwap" src="img/red.png">

<select id="colour" onChange="swapImage()">
<option value="img/red.png">Red</option>
<option value="img/green.png">Green</option>
</select>

Here's my javascript:

<script type="text/javascript">
function swapImage(){
    var image = document.getElementById("imageToSwap");
    var change = document.getElementById("colour");
    image.src = change.value;   
};
</script>

@AspiringAqib Thus far, I only know how to do it for 1 select, but not multiple select. there. — Yoshi
– Yoshi, Commented Dec 28, 2012 at 13:05

Yoshi · Accepted Answer · 2012-12-28 13:10:28Z

1

var
  img = document.getElementById('imageToSwap'),
  colour = document.getElementById('colour'),
  size = document.getElementById('size'),
  change;

change = function (evt) {
  img.src = ['img/', size.value, '_', colour.value, '.png'].join('');
};

colour.addEventListener('change', change, false);
size.addEventListener('change', change, false);

with:

<img id="imageToSwap">

<select id="colour">
  <option value="red">Red</option>
  <option value="green">Green</option>
</select>

<select id="size">
  <option value="small">Small</option>
  <option value="big">Big</option>
</select>

demo: http://jsbin.com/iwezad/2/

though, using jQuery this could be shortend a lot, and you'd get rid of some browser quirks regarding addEventListener.

jQuery version:

$('#colour, #size').on('change', function() {
  $('#imageToSwap').prop('src', 
    ['img/', $('#size').val(), '_', $('#colour').val(), '.jpg'].join('')    
  );
});

edited Dec 28, 2012 at 13:10

answered Dec 28, 2012 at 13:04

Yoshi

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1 Comment

Yoshi Over a year ago

@ATOzTOA Unobtrusive JavaScript

ATOzTOA · Accepted Answer · 2012-12-28 13:04:46Z

1

You can always concatenate values from selects.

<img id="imageToSwap" src="img/red.png">

<select id="colour" onChange="swapImage()">
    <option value="red.png">Red</option>
    <option value="green.png">Green</option>
</select>

<select id="size" onChange="swapImage()">
    <option value="small">Small</option>
    <option value="large">Large</option>
</select>

And in script:

<script type="text/javascript">
    function swapImage(){
        var image = document.getElementById("imageToSwap");
        var color = document.getElementById("colour").value;
        var size = document.getElementById("size").value;

        image.src = "img/" + size + "_" + color;
    };
</script>

answered Dec 28, 2012 at 13:04

ATOzTOA

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Comments

Prashant16 · Accepted Answer · 2012-12-28 13:18:09Z

0

<img id="imageToSwap" >
<select id="colour"  onchange="swapImage()">
<option value="red">Red</option>
<option value="green">Green</option>
</select>

<select id="size" onchange="swapImage()">
<option value="small">Small</option>`
<option value="large">Large</option>
</select>

Javascript code:

<script type="text/javascript" language="javascript">
    function swapImage() {
        var image = document.getElementById("imageToSwap");
        var color = document.getElementById("colour").value;
        var size = document.getElementById("size").value;
        var imagename = size + '_' + color + '.png';

        image.src = "img/" + imagename;
    }
</script>

answered Dec 28, 2012 at 13:18

Prashant16

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