Facing Error While using PHP Simple HTML DOM Parser

Question

I am using PHP Simple HTML DOM Parser to fetch urls, but i got an error while fetching links. Have a look at this script:

$result = str_get_html($result);
foreach($result->find('a') as $element)
$result = str_get_html($result);
$result = str_replace('http://', '', $result);
foreach($result->find('a') as $elementa)
echo $element->href;
echo $elementa->href;

Here I want to fetch all links for twice, first time urls in $element->href will fetch links starting with http:// and in $elementa->href will fetch links without http://.

But this shows only a blank page. Any idea?

Niloct · Accepted Answer · 2012-09-18 05:15:44Z

1

$result = str_get_html($result);
$arrWithPrefix = array();
$arrWithoutPrefix = array();
foreach ($result->find('a') as $link) {
    $arrWithPrefix[] = $link->href;
    $arrWithoutPrefix[] = str_replace('http://', '', $link->href);
}
var_dump($arrWithPrefix);
var_dump($arrWithoutPrefix);

Not tested, see if it is any good :)

answered Sep 18, 2012 at 5:15

Niloct

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6 Comments

Niloct Over a year ago

Do you want the entire <A> tag for each element ?

Niloct Over a year ago

Could you please edit your question with a sample input HTML and the unexpected output from the above script ?

user1679212 Over a year ago

Thanks for your reply.. please take some time visiting here codepad.org/TWIYdkX3 and look what to do to do the exact i want to do.. Thanks again

Niloct Over a year ago

Skimming, I saw that you're pasting the component source code in your script (I presume for running the app on codepad). Try this: in the extracted folder for the zip file you downloaded from their website, copy and paste this to a test.php file inside the folder app. Notice that it refers to the php file in the folder above it, so be certain that it is there. Try this and then tell us what happens. **Edit: fixed source.

user1679212 Over a year ago

thanks, but i ama php learner so cant understand why it showing lots of texts like } array(16) { [0]=> string(161) " .... how to make it clean .Thanks

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Rajat Modi · Accepted Answer · 2012-09-18 12:06:30Z

1

you can also use this code it will set the http:// sitename to the link and will return all links with one link

foreach ($html->find('a') as $e) {
   $cssHrefs = $e -> href;
   preg_match_all('~' . SITE_NAME . '~is', $cssHrefs, $match);
   if (count($match[0]) == 0) {
        $loadedHrefs[] = SITE_NAME . $cssHrefs;
   } else {
        $loadedHrefs[] = $cssHrefs;
}
var_dump($loadedHrefs);

answered Sep 18, 2012 at 12:06

Rajat Modi

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Comments

blömpæ · Accepted Answer · 2012-09-18 18:04:25Z

0

u may try this as well

$result = str_get_html($result);
foreach($result->find('a') as $element){
$result = str_get_html($result);
$result = str_replace('http://', '', $result);
}
foreach($result->find('a') as $elementa){
echo $element->href;
echo $elementa->href;
}

answered Sep 18, 2012 at 18:04

blömpæ

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