Shell Script: Menu driven script taking in multiple options

Question

I need some suggestions for my menu driven shell script. I would like the end user of this script to be able to provide multiple options when prompted to enter the choice. The user can also enter 1 option or he/she can enter multiple options.

For eg. the script should be able to handle both options:

Please enter any option or options between [1 - 4]: 1 2 3 

Please enter any option or options between [1 - 4]: 1

Please let me know how can I made changes to my script to reflect this.

Below is the code of my script for your reference:

#!/bin/sh

while :
do
 clear
 echo " ******** Task performing script ******** "
 echo "1. task1 "
 echo
 echo "2. task2 "
 echo
 echo "3. task3"
 echo
 echo "4. Exit"
 echo
 echo -n "Please enter any option or options between [1 - 4]"
     read opt;
 case $opt in
1)
 echo "Performing task1 . . . .";
 for i in `cat test`
 do
 ...............
 ...............
 done;;
2)
 echo "Performing task2 . . . .";
 for i in `cat test`
 do
 ...............
 ...............
 done;;
3)
 echo "Performing task3 . . . .";
 for i in `cat test`
 do
 ...............
 ...............
 done;;
4)
 echo "Bye $USER";
 exit 1;;
*)
 echo "$opt is an invaild option";
 echo "Press [enter] key to continue. . .";
 read enterKey;;
  esac
done

chepner · Accepted Answer · 2012-09-17 18:34:33Z

2

Wrap your case statement in a for loop that iterates over the value you get from the read statement.

while : do;
    # print menu
    read opts

    for opt in $opts; do  # To allow for multiple space-separated choices

        case $opt in
        ...
        esac
    done
done

answered Sep 17, 2012 at 18:34

chepner

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1 Comment

sk2code Over a year ago

I updated my code as per your suggestion but it is still not working: echo -n "Please enter option [1 - 6]" read opts for opt in $opts; do case $opt in ............... esac done done

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