Python from within Python

Question

I'm trying to launch a simple server from a Python script:

    server = Popen(['python' ,'-m', 'SimpleHTTPServer', '9090'], stderr=STDOUT, stdout=PIPE)
    output = server.communicate()[0]  # <- DEBUG

Reading the output, I see:

'/usr/bin/python: Import by filename is not supported.'

What's the problem? How to solve it?

Works fine for me. Make it log to the screen directly. Let's see what it says. Also, don't import Popen and the rest of subprocess into your current namespace. — Noufal Ibrahim
– Noufal Ibrahim, Commented Jun 1, 2012 at 13:00
can't log to the screen as it is withing a library and it's not a console application. — pistacchio
– pistacchio, Commented Jun 1, 2012 at 13:02
+1 to Noufal - my guess is that it's environmental - the "python" being invoked by Popen ('/usr/bin/python' based on the output) might be a different version, but one of the PYTHON...PATH environment variables might be pointing somewhere else... — Pamela McA'Nulty
– Pamela McA'Nulty, Commented Jun 1, 2012 at 13:49

user10819040 · Accepted Answer · 2018-12-21 07:50:49Z

1

I suggest change to code to this:

import SimpleHTTPServer
import SocketServer

PORT = 9090

Handler = SimpleHTTPServer.SimpleHTTPRequestHandler

httpd = SocketServer.TCPServer(("", PORT), Handler)

print "serving at port", PORT
httpd.serve_forever()

answered Dec 21, 2018 at 7:50

user10819040

Sign up to request clarification or add additional context in comments.

1 Comment

tripleee Over a year ago

This has the decided disadvantage that the script cannot perform other tasks while the server runs in the background.

Collectives™ on Stack Overflow

Python from within Python

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related