Java Regex to find substring

Question

I have following string "Class (102) (401)" and "Class (401)" i want to find regex to find substring which always return me last bracket value in my case it is '(401) '

Following is my code

Pattern MY_PATTERN = Pattern.compile(".*(\\(\\d+\\))");
    Matcher mat = MY_PATTERN.matcher("Class (102) (401)");
    while (mat.find()){
        System.out.println(mat.group());
    }

It is returning

--( --) --( --)

How about getting the index of the last ( and ) and getting the substring between the two? — Chetter Hummin
– Chetter Hummin, Commented May 3, 2012 at 8:23

codaddict · Accepted Answer · 2012-05-03 08:14:12Z

2

You can use:

Pattern MY_PATTERN = Pattern.compile(".*(\\(\\d+\\))");

See it

answered May 3, 2012 at 8:14

codaddict

457k83 gold badges501 silver badges537 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

d-man Over a year ago

i tried and it returns "Class (102) (401)" i want only last value which is in last bracket '401'

codaddict Over a year ago

@Faisalkhan: You need to use group(1). See the working link.

d-man Over a year ago

one more small help if i want 401 instead (401) then what will be the change ?

codaddict Over a year ago

@Faisalkhan: Use the pattern: ".*\$(\\d+)\$"

Cylian · Accepted Answer · 2012-05-03 08:30:50Z

Try this:

(?<=\()[^\)(]+(?=\)[^\)\(]+$)

Explanation:

<!--
(?<=\()[^\)(]+(?=\)[^\)\(]+$)

Options: ^ and $ match at line breaks; free-spacing

Assert that the regex below can be matched, with the match ending at this position (positive lookbehind) «(?<=\()»
   Match the character “(” literally «\(»
Match a single character NOT present in the list below «[^\)(]+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
   A ) character «\)»
   The character “(” «(»
Assert that the regex below can be matched, starting at this position (positive lookahead) «(?=\)[^\)\(]+$)»
   Match the character “)” literally «\)»
   Match a single character NOT present in the list below «[^\)\(]+»
      Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
      A ) character «\)»
      A ( character «\(»
   Assert position at the end of a line (at the end of the string or before a line break character) «$»
-->

Hachi · Accepted Answer · 2012-05-03 08:40:19Z

1

how about the expression: .*\$([^\\(\$]+)\\)[^\$\$]*$

it finds a ( followed by non-brackets [^\$\$] (your desired string) followed by a ) and after that are only non-brackets allowed, so it must be the last

answered May 3, 2012 at 8:40

Hachi

3,2991 gold badge24 silver badges29 bronze badges

Collectives™ on Stack Overflow

Java Regex to find substring

3 Answers 3

4 Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

4 Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related